fallon bắt đầu chủ đề từ 1 tuần trước

@Alish ·

I was recently asked a Java interview question which required me to complete a method task with only one pass through an input array. I stated that it was not possible to do this with a single pass, but the interviewer ended the interview without providing an answer. __

public class SortedArrayOps {  
    public SortedArrayOps() {  


//    Print at the system out the first two ints found in the sorted array: sortedInts[] whose sum is equal to Sum in a single pass over the array sortedInts[] with no 0 value allowed.  
//  i.e. sortedInts[i] + sortedInts[?] = Sum where ? is the target index to be found to complete the task.  
static void PrintIntSumValues(int Sum, int sortedInts[]) {  
//        need to test to see if the Sum value is contained in the array sortedInts. And, if not do nothing.  
    for(int i=0; i<sortedInts.length; i++) {  
//            ... do some work: algebra and logic ...  
//            System.out.println sortedInts[i]+sortedInts[?] sums to Sum.  

public static void main(String[] args) {  
    final int[] sortedArray = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50};
    PrintIntSumValues(48, sortedArray);  

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